tan 1 tan 10 tan 20 tan 70 tan 80 tan 89 = 1
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7
tan(90-1)×tan(90-10)×tan(90-20)×tan70 x tan80× tan89 =1
cot89×cot80×cot70×tan70×tan80×tan89
we know that cot@=1/tan@
so,
1/tan89×1/tan80×1/tan70×tan89×tan80×tan70=1
HENCE PROVED.
I hope this will help you and it does than please follow me.
cot89×cot80×cot70×tan70×tan80×tan89
we know that cot@=1/tan@
so,
1/tan89×1/tan80×1/tan70×tan89×tan80×tan70=1
HENCE PROVED.
I hope this will help you and it does than please follow me.
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Answered by
16
Hey there !!
Answer: 1 .
Step-by-step explanation:
= tan 1 . tan 10 . tan 20 . tan 70 . tan 80 . tan 89
= tan 1 . tan 10 . tan 20 . tan( 90 - 20 ) ... tan (90 - 10 ) . tan ( 90 - 1)
= tan 1 . tan 10 . tan 20 . cot 20 . cot 10 . cot 1
= tan 1 . cot 1 . tan 10 . cot 10 . tan 20 . cot 20 .
= 1 x 1 x 1.
= 1 .
Hence, it is solved .
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#BeBrainly .
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