Question

tan-1 V3 - sec-1(-2) is equal to​

Answer 1

Step-by-step explanation:

I am class 10 but don't worry

tan-¹I root 3

let y=tan-¹ root 3

tan y=root3

tany=tan[n/3]

rang of principle value

of tan-¹ is [-n/2,pie/2]

hope it helps tank you

this much I know