Math, asked by bvhakap, 11 months ago

tan^-1(x+1)+tan^-1(x-1) =tan^-1(8/31) समीकरण को हल कीजिए​

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Answered by Anonymous
3

Answer:

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Answered by Anonymous
5

Step-by-step explanation:

tan^-1(x+1)+tan^-1(x-1) =tan^-1(8/31)

tan^-1{(x+1) +(x-1)} /(1 - x^2 +1 )= tan^-1(8/31)

2x/(2-x^2) = 8/31

8x^2 +62x - 16= 0

8x^2 + 64x - 2x - 16 = 0

8x(X + 8 ) - 2(X +8)

X = 1/4 and -8

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