tan(1-x/1+x)=1/2tan
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Answer:
tan¯¹ 1-x/1+x = 1/2 tan¯¹ x, (x > 0)
2tan¯¹ (1+x / 1-x) = tan¯¹x
tan¯¹ ( (2-2x / 2 +2x) / (1- (1-x/1+x)²) ) = tan¯¹ x
⇒ 2(1-x / 1+x) / {(1+x)² - (1-x)²} / (1+x)²
⇒ x = 2-2x / [(1+x² +2x -1-x² + 2x) / (1+x) ]
⇒ x = 2-2x / [ 4x / 1+x ]
⇒ x = 2-2x (1+x) / 4x
⇒ 2 + 2x -2x - 2x² = 4x²
⇒ 2x² + 4x² -2 = 0
⇒ 6x² - 2 = 0
⇒ 2 (3x²-1) =0
⇒3x² -1 =0
⇒ 3x² = 1
⇒ x² = 1/3
⇒ x = +- 1/√3
given that x>0
∴ x = +1/√3
Step-by-step explanation:
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