tan 10 +tan 35 +tan 10×tan 35=?
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Answered by
2
we know tan (A+B) = (tan A +tan B)/(1- tan A tan B)
put A = 10° and B = 35°
to get tan 45° = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)
or 1 = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)
or (1- tan 10° tan 35°) = ( tan 10 ° + tan 35°)
or Tan35°+tan10°+tan35°tan10°= 1
HENCE VERIFIED
put A = 10° and B = 35°
to get tan 45° = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)
or 1 = ( tan 10 ° + tan 35°)/(1- tan 10° tan 35°)
or (1- tan 10° tan 35°) = ( tan 10 ° + tan 35°)
or Tan35°+tan10°+tan35°tan10°= 1
HENCE VERIFIED
Answered by
0
Answer:
tan10°+tan35°+tan10°.tan35°=1
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