tan 10° tan 15° tan 75° tan 80° = 1
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Answered by
8
tan 10 tan 80 tan15 tan 75 = 1
tan (90-80).tan 80 tan15 tan (90-15) = 1
tan (90- @) = Cot @
Cot 80.Tan 80 tan 15.Cot 15= 1
we know that 1/cot = tan
1/tan80×tan 80 1/ cot 15× cot 15 = 1
1= 1
tan (90-80).tan 80 tan15 tan (90-15) = 1
tan (90- @) = Cot @
Cot 80.Tan 80 tan 15.Cot 15= 1
we know that 1/cot = tan
1/tan80×tan 80 1/ cot 15× cot 15 = 1
1= 1
mohduzairali16:
thnx buddy
Answered by
8
Hey
To prove :-
tan 10° tan 15° tan 75° tan 80° = 1
= tan 10° tan 15° tan ( 90° - 15°) tan(90° - 10° )
= tan 10° tan 15° cot 15° cot 10°
= tan 10° * 1 / tan 10° * tan 15° * 1 / tan 15°
= 1 * 1
= 1
thanks :)
To prove :-
tan 10° tan 15° tan 75° tan 80° = 1
= tan 10° tan 15° tan ( 90° - 15°) tan(90° - 10° )
= tan 10° tan 15° cot 15° cot 10°
= tan 10° * 1 / tan 10° * tan 15° * 1 / tan 15°
= 1 * 1
= 1
thanks :)
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