Question

tan 10°.tan 30°.tan 50°. tan 70°​

Answer 1

Step-by-step explanation:

tan10

∘

tan20

∘

tan30

∘

tan40

∘

tan50

∘

tan60

∘

tan70

∘

tan80

∘

we know that tan(90−θ)=cotθ

=tan10

∘

.tan20

∘

.tan30

∘

.tan40

∘

.cot40

∘

.cot30

∘

.cot20

∘

.cot10

∘

=1...........Use tan(90

o

−θ)=cotθ and tanθcotθ=1