tan 10º.cos 20°.tan 40°.tan 50°.cosec 70°.sec 80°.sin 80° = 1
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Answer:
yes answer is 1
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Answer:
sin10cos20tan40tan50cosec70sec80∘=1
=(sin10sec80)(cos20cosec70)(tan40+tan50)
=(sin(90−80)sec80)(cos(90−70)cosec70)(tan(90−50)tan50)
=(cos80⋅sec80)(sin70cosen70)⋅tan(cot50tan50)
=1.1.1
=1.1
=RHS
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