Math, asked by jiyamayu, 10 months ago

tanѲ=11
find the values of the other trigonometric ratios.

plzz help mee with this!​

Answers

Answered by tomd29181
2

1+tan^2x=sec^2x

sec^2x=1+121=122

secx=root122

cosx=1/secx

cosx=1/root 122

sinx=tanxcosx

sinx=11 ×1/root122

sinx=11/root 122

cosec x=1/sinx

cosec x= root 122/11

cotx=1/tanx

cotx=1/11

hope it helps u

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