Math, asked by ramafhv69, 1 year ago

tan 15° ==>??????????????? ​

Answers

Answered by superjunior
4

Answer:

√3 - 1 /√3+ 1

Step-by-step explanation:

tan 15° = tan(45° - 30°)

= tan 45° - tan 30°/ 1+ tan 45° × tan 30°

[∵tan(A-B) = tanA - tanB/1 + tan A .tanB ]

⇒ 1 - 1/√3 / 1+1× 1/√3

⇒ √3 -1 /√3 +1 / √3 +1 / √3

√3 -1 / √3 + 1

Similar questions