tan 15° ==>???????????????
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Answer:
√3 - 1 /√3+ 1
Step-by-step explanation:
∵ tan 15° = tan(45° - 30°)
= tan 45° - tan 30°/ 1+ tan 45° × tan 30°
[∵tan(A-B) = tanA - tanB/1 + tan A .tanB ]
⇒ 1 - 1/√3 / 1+1× 1/√3
⇒ √3 -1 /√3 +1 / √3 +1 / √3
⇒√3 -1 / √3 + 1
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