tan 15° + tan 30° =?
Answers
Answered by
3
Tan15=2-3rote
Tan30=1/3rote
Tan15+Tan30=2-4/3rote
Tan30=1/3rote
Tan15+Tan30=2-4/3rote
Answered by
11
Hi ,
Tan 15 = tan ( 45 - 30 )
= ( Tan 45 - tan30)/ (1 + tan45tan30)
= ( 1 - 1/√3 ) / ( 1+ 1/√3 )
= ( √3 - 1 ) / ( √3 + 1 )
H
Rationalize the denominator ,
= ( √3 - 1 )² / [ ( √3 )² - 1² ]
= ( 4 - 2√3 ) / 2
= 2 - √3 ----( 1 )
Now ,
Tan 15 + tan 30
= 2 - √3 + 1/√3
= 2 - √3 + ( √3 ) / 3
= ( 6 - 3√3 + √3 )/ 3
= ( 6 - 2√3 ) / 3
I hope this helps you.
:)
Tan 15 = tan ( 45 - 30 )
= ( Tan 45 - tan30)/ (1 + tan45tan30)
= ( 1 - 1/√3 ) / ( 1+ 1/√3 )
= ( √3 - 1 ) / ( √3 + 1 )
H
Rationalize the denominator ,
= ( √3 - 1 )² / [ ( √3 )² - 1² ]
= ( 4 - 2√3 ) / 2
= 2 - √3 ----( 1 )
Now ,
Tan 15 + tan 30
= 2 - √3 + 1/√3
= 2 - √3 + ( √3 ) / 3
= ( 6 - 3√3 + √3 )/ 3
= ( 6 - 2√3 ) / 3
I hope this helps you.
:)
DxT:
can you please check the calucation of last two steps
its correct
it can be simplify one more step
2-(2√3/3)
yeah he did it in short but correctly
yah
rememebering tan15 is difficult , so that i explained completely .
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