Question

tan 15° + tan 75° + cot 15° + cot 75º =​

Answer 1

Answer:

tan15° + tan75° + cot15° + cot75°

#Hope this attachment will help you

Answer 2

Answer:

8

Step-by-step explanation:

formula used :

tan(90-∅) = cot∅

cot(90-∅) = tan∅

tan∅ = 1/cot∅

cot∅ = 1/tan∅

tan∅ × cot∅ = 1

tan75 = 2 + √3

cot75 = 2 - √3

tan15 + tan75 + cot15 + cot75

=> tan15 + tan75 + 1/tan15 + 1/tan75

=> (tan15 × tan75 + 1)/tan15 + (tan75 × tan15 + 1)/tan75

=> (cot75 × tan75 + 1)/tan15 + (tan75 × cot75 + 1)/tan75

=> (1 + 1)/tan15 + (1 + 1)/tan75

=> 2/tan15 + 2/tan75

=> 2(tan75 + tan15)/tan15*tan75

=> 2(tan75 + tan15)/cot75*tan75

=> 2(tan75 + tan15)

=> 2(tan75 + cot75)

=> 2(2 + √3 + 2 - √3)

=> 2(4)

=> 8

thanks,

#SPJ3