Tan 15degree +Oct 15degree=4
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tan 15 = tan (45-30)
= tan 45 - tan 30)/ 1+ tan 45 tan 30
= 1-1/√3)/1+1/√3
√3 - 1)/√3+1
4-2√3)/2
2- √3
cot 15 = 1/(2-√3)
= 2+√3
add 2+√3,+ 2 - √3,= 4
= tan 45 - tan 30)/ 1+ tan 45 tan 30
= 1-1/√3)/1+1/√3
√3 - 1)/√3+1
4-2√3)/2
2- √3
cot 15 = 1/(2-√3)
= 2+√3
add 2+√3,+ 2 - √3,= 4
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