Question

tan^2/1+tan^2+cot^2/1+cot^2=1​

Answer 1

Answer:

1+tan2θ=1+tan2θ11+tan2θ

(1−cotθ1−tanθ)2=(tan2θtan2θ+1)1+tan2θ

=⎝⎜⎜⎛1−tanθ11−tanθ⎠⎟⎟⎞2=tan2θ

(tanθ(tanθ−11−tanθ))2

=(−tanθ)2

=tan2θ.

Step-by-step explanation:

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