Question

tan^2 28°-sec^2 28°=​

Answer 1

Step-by-step explanation:

Rearrange the equation as follows

(sin

2

28+sin

2

62)+tan

2

38−cot

2

52+

4

1

sec

2

30

=(sin

2

28+cos

2

(90−28))+tan

2

38−cot

2

52+

4

1

sec

2

30

=(sin

2

28+cos

2

28)+tan

2

38−cot

2

52+

4

1

sec

2

30

=1+tan

2

38−cot

2

52+

4

1

sec

2

30

NOTE:1+tan

2

θ=sec

2

θ

=sec

2

38−cot

2

52+

4

1

sec

2

30

=csc

2

52−cot

2

52+

4

1

sec

2

30

=1+

4

1

sec

2

30

sec30=

3

2

=1+

4

1

(

3

4

)

=

3

4