(tanΦ+2)(2tanΦ+1)=5tanΦ+secΦ
Answers
Answered by
0
LHS= (tan¢ +2)(2tan¢+1)
=2tan²¢ +tan¢+4tan¢+2
=5tan¢ +2(1+tan²¢)
=5 tan¢ +2 sec²¢
LHS = RHS.
proved.
please mark me brainliest
=2tan²¢ +tan¢+4tan¢+2
=5tan¢ +2(1+tan²¢)
=5 tan¢ +2 sec²¢
LHS = RHS.
proved.
please mark me brainliest
Similar questions