tan^2(30)° + tan^2(60)°=???
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Answered by
1
tan^30 + tan^60
=[ tan 30 ]^2 + [tan 60]^2
= [ 1/root3]^2 + [ root 3]^2
=1/3 + 3
= 1/3 + 9/3
= 10/3.
=[ tan 30 ]^2 + [tan 60]^2
= [ 1/root3]^2 + [ root 3]^2
=1/3 + 3
= 1/3 + 9/3
= 10/3.
Answered by
2
tan 30= 1/√3
tan 60= √3
Therefore,
tan²30= 1/3
tan²60= 3
1/3 + 3= 1+9/3= 10/3
tan 60= √3
Therefore,
tan²30= 1/3
tan²60= 3
1/3 + 3= 1+9/3= 10/3
ganga24:
10/√3 is perfect answer
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