tan^2(3a +15)-1=0 find the value of A
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Answer:
a=10
Step-by-step explanation:
=> tan² ( 3A + 15 )° - 1 = 0
Adding 1 to both sides,
=> tan² ( 3A + 15 )° - 1 + 1 = 0 + 1
=> tan² ( 3A + 15 )° = 1 --------- ( 1 )
We know that,
=> tan 45° = 1
Squaring both sides,
=> ( tan 45° )² = 1²
=> tan² 45° = 1 ------------ ( 2 )
From ( 1 ) and ( 2 ),
=> tan²( 3A + 15 )° = tan² 45°
As the trigonometric ratios are equal, so angle will be also equal.
=> ( 3A + 15 )° = 45°
=> 3A + 15 = 45
=> 3A = 45 - 15
=> 3A = 30
=> A = 30 ÷ 3
•°• A = 10.
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