Question

tan^2 45 -sin 45 -cos 45+√2​

Answer 1

Answer:

1

Step-by-step explanation:

${ \tan}^{2}(45) - \sin(45) - \cos(45) + \sqrt{2} \\ = {(1)}^{2} (- 1 \div \sqrt{2}) (- 1 \div \sqrt{2} ) + \sqrt{2} \\ = ( \sqrt{2} - 1 - 1 + 2) \div \sqrt{2} \\ = ( \sqrt{2} - 2 + 2) \div \sqrt{2} \\ = \sqrt{2} \div \sqrt{2} \\ = 1$

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Answer 2

Step-by-step explanation:

• tan45=1
• (1)>2-1/root2-1/root2+root2
• 1-1/ root 2-1/ root2+root2
• 1-root2*root2
• 1-2
• =1