tan^2 60 +cos^2 45 +sec^2 30+5cos^290 / cosec30 +sec60-cot^230
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the photo shows the solution of the given equation
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Answered by
3
Answer:
Given that:
csc30+sec60−cot
2
30
tan
2
60+4sin
2
45+3sec
2
30+5cos
2
90
=
2+2−(
3
)
2
(
3
)
2
+4×(
2
1
)
2
+3×(
3
2
)
2
+5×0
=
4−3
3+4×
2
1
+3×
3
4
+0
=
1
3+2+4+0
=9
Step-by-step explanation:
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