Question

tan 2 60° + 4 cos 2 45° + 3 sec 2 30° + 5 cos 2 90º =​

Answer 1

Step-by-step explanation:

(tan^2 60+4cos^2 45 + 3sec^2 30+5cos^2 90) ./(cosec 30 + sec 60 - cot^2 30)

={(√3)^2 + 4×(1/√2)^2 + 3×(2/√3)^2+ 5×0^2} /{2+2-(√3)^2

={(3+4×(1/2) +3×(4/3)+0)}/(4–3)

=3+2+4=9

Answer 2

Answer:

${ \tan }^{2} (60) + 4 { \cos }^{2}(45) + 3 { \sec }^{2} (30) + 5 { \cos }^{2} (90)$

$⟹ {( \sqrt{3}) }^{2} + 4 ({ \frac{1}{ \sqrt{2} }) }^{2} + 3 ({ \frac{2}{ \sqrt{3} }) }^{2} + 5 {(0)}^{2}$

$⟹3 + 2 + 4 + 0$

$⟹9$