Question

tan^2 60° +4cos^2 45°+3sec^2 30° +5cos^2 90°/ cosec30°+ sec60°-cot^2 30°​

Answer 1

(tan^2 60+4cos^2 45 + 3sec^2 30+5cos^2 90) ./(cosec 30 + sec 60 - cot^2 30)

={(√3)^2 + 4×(1/√2)^2 + 3×(2/√3)^2+ 5×0^2} /{2+2-(√3)^2

={(3+4×(1/2) +3×(4/3)+0)}/(4–3)

=3+2+4=9

Answer 2

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