Question

Tan^2 60°+4cos^2 45°+sec^2 30°+5cos^2 90°/cosec 30°+sec60°-cot^2 30°

Answer 1

pls refer my attachment;

hope it helps u dear❤✌✌

Answer 2

$\dfrac{tan²60°+4cos²45°+3sec²30°+5cos²90°}{cosec30°+sec60°-cot²30°}$

$\dfrac{{(√3)}^{2}+4×({\dfrac{1}{√2})}^{2}+3× {(\dfrac{2}{√3})} ^{2}+5× {(0)}^{2} }{2+2-{(√3)} ^ {2}}$

$\dfrac{3 + 2 + 4 + 0}{2 + 2 - 3}$

$\dfrac{9}{1}$

$9$