Math, asked by panditsheal, 9 months ago

tan^2 65°- cosec^2 25°+ 1/
cosec^2 65°- tan^2 25° + 2 ​

Answers

Answered by sritejatalluri
4

Answer:

tan*2 65 - cosec*2 (90-65) +1 --------------- {1}

[cosec*2 (90-x)] = sec*x

tan*2 65 - sec*2 65 + 1

( sec*2 x - tan*2 x = 1) ----------> -(tan*2 x - sec*2 x ) = -1

substitute this in eq.1

-1 + 1 = 0

cosec*2 65 - tan*2 25 +2 =

from the above cosec*2 65 = sec*2 25

sec*2 25 - tan*2 25 = 1 (sec*2 x - tan*2 x = 1)

1 + 2 = 3

tan*2 65 - cosec*2 25 + 1/cosec*2 65 - tan*2 25 + 2

0/3 = 0

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