tan^2 A-1/cos^2A if sin 3A=1 and 0<= A<=90°
Answers
Answered by
0
Answer:
Sin 3A = 1
Sin 3A = sin 90
3A = 90
A = 90/3
A = 30
Tan^2(30) - 1 /cos^2(30)
(1/^3)^2 / (^3/2)^2
1/3 / 3/2
1/3*2/3
1/2
Answered by
0
Answer:
-8/9
Step-by-step explanation:
sin 3A=1
Sin 90°=1 (from trigonometric tables)
So, sin 3A=sin 90°
Cancel sin from both sides and we get
3A=90°=>A=30°
after putting this value in the equation tan^2A-1/cos^2A
We get
-8/9
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