Math, asked by priyanshumeher, 4 months ago

tan^2 A-1/cos^2A if sin 3A=1 and 0<= A<=90°​

Answers

Answered by koritalasailakshmi
0

Answer:

Sin 3A = 1

Sin 3A = sin 90

3A = 90

A = 90/3

A = 30

Tan^2(30) - 1 /cos^2(30)

(1/^3)^2 / (^3/2)^2

1/3 / 3/2

1/3*2/3

1/2

Answered by shubhambrainly8
0

Answer:

-8/9

Step-by-step explanation:

sin 3A=1

Sin 90°=1 (from trigonometric tables)

So, sin 3A=sin 90°

Cancel sin from both sides and we get

3A=90°=>A=30°

after putting this value in the equation tan^2A-1/cos^2A

We get

-8/9

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