Question

tan^2 A + cot^2 A = sec^2 A cosec^2 A - 2​

Answer 1

Answer:

Proved it

Step-by-step explanation:

First write tan and cot in left hand side in terms of sin and cos

I wrote :-

${ \sin(x) }^{4} + { \cos(x) }^{4} = {( { \sin(x) }^{2} + { \cos(x) }^{2} )}^{2} - 2 { (\sin(x) \cos(x)) }^{2}$

Using (a+b )^2 - 2ab = a^2 + b^2

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