Question

tan^2 A- tan^2 B = cos^2 B-cos^2A/
cos^2 B × cos^2 A =
sin^2A - sin^2 B/
cos^2 B cos^2 A​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

L.H.S.

》tan²A-tan²B

》Using Identity tan²A=sec²A-1

》sec²A-1-(sec²B-1)

》sex²A-1-(sex²B+1)

》sec²A-sec²B

》1/cos²A-1/cos²B

*Taking L.C.M.

》{cos²B-cos²A)/(cos²B-cos²A).

!Hence It Is Proved...