tan ² ∅- sin²∅ = tan²∅·sin²∅
Terdweryiu2003:
this is a trigonometrical identity
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Hi friend,
Tan²Theta - Sin²theta = Tan²Theta × Sin²theta
LHS = Tan²Theta - Sin²theta
=> Sin² theta/ Cos²theta - Sin²theta
=> Sin²theta - Sin²theta Cos²theta/ Cos²theta
=> Sin²theta (1-Cos²theta)/Cos²theta
=> Sin²theta/Cos²theta × Sin²theta
=> Tan²× Sin²theta = RHS.
Hence,
LHS = RHS.... PROVED....
HOPE IT WILL HELP YOU..... :-)
Tan²Theta - Sin²theta = Tan²Theta × Sin²theta
LHS = Tan²Theta - Sin²theta
=> Sin² theta/ Cos²theta - Sin²theta
=> Sin²theta - Sin²theta Cos²theta/ Cos²theta
=> Sin²theta (1-Cos²theta)/Cos²theta
=> Sin²theta/Cos²theta × Sin²theta
=> Tan²× Sin²theta = RHS.
Hence,
LHS = RHS.... PROVED....
HOPE IT WILL HELP YOU..... :-)
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