Math, asked by Terdweryiu2003, 1 year ago

tan ² ∅- sin²∅ = tan²∅·sin²∅


Terdweryiu2003: this is a trigonometrical identity
Terdweryiu2003: please solve
Terdweryiu2003: see this query

Answers

Answered by RishabhBansal
53
Hey!!!!

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Refer to the attachment

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Hope this helps ✌️
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Terdweryiu2003: thankyou bro
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Answered by Panzer786
18
Hi friend,

Tan²Theta - Sin²theta = Tan²Theta × Sin²theta

LHS = Tan²Theta - Sin²theta

=> Sin² theta/ Cos²theta - Sin²theta

=> Sin²theta - Sin²theta Cos²theta/ Cos²theta

=> Sin²theta (1-Cos²theta)/Cos²theta


=> Sin²theta/Cos²theta × Sin²theta

=> Tan²× Sin²theta = RHS.

Hence,

LHS = RHS.... PROVED....


HOPE IT WILL HELP YOU..... :-)

Terdweryiu2003: thankyou bro
Terdweryiu2003: Again
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