Math, asked by gbsubasree, 4 months ago

Tan^2 theta /1+tan2 theta + cot 2 theta / 1+cot 2 theta =1

Answers

Answered by sandy1816

3

Answer:

tan²a/1+tan²a+cot²a/1+cot²a

=tan²a/sec²a+cot²a/cosec²a

=sin²a/cos²a×cos²a+cos²a/sin²a×sin²a

=sin²a+cos²a

=1

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