tan^2(theta+ π/3 ) = 0, find general solution.
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Answered by
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Step-by-step explanation:
tan ² (pie/3)=0
hope this may help u
Answered by
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Answer:
a = 300°
Step-by-step explanation:
Actually I don't have a keyboard key to type theta so, I am using the variable "a" instead of the Greek letter theta.
tan²(a + π/3) = 0
| ∵ tan(A + B) = (tan A + tan B)/(1 - tan A.tan B)
| =>tan²(A + B) = [(tan A+tan B)/(1 - tan A.tan B)]²
|
|...........=> [(tan a+tan π/3)/(1 - tan a.tan π/3)]² = 0
=> [(tan a + √3)/(1 - √3 tan a)]² = 0
=> (tan a + √3)²/(1 - √3 tan a)² = 0
=> (tan a + √3)² = 0 {Assuming, (1 - √3tan a)² ≠ 0)
=> tan a = - √3 => tan a = tan 300°
=> a = 300°
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