Question

(tan^2 theta)/(b * n ^ 2 * theta) + (sin c ^ 2 * theta)/(sec^2 theta - l * sin^2 theta) = 1/(sin^2 theta - cos^2 theta)

Answer 1

Step-by-step explanation:

(tan^2 theta)/(b * n ^ 2 * theta) + (sin c ^ 2 * theta)/(sec^2 theta - l * sin^2 theta) = 1/(sin^2 theta

Answer 2

Answer:

Please can you upload screenshot of this question.

Step-by-step explanation:

I don't understand this question.