tan^2 theta + sin^2 theta - cis 2 thta
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I think ur question is wrong
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sin
2
θ
+
cos
2
θ
tan
2
θ
=
cot
2
θ
Explanation:
Recall from our trigonometric identities that
sin
2
θ
+
cos
2
θ
=
1
. Then the expression becomes:
sin
2
θ
+
cos
2
θ
tan
2
θ
=
1
tan
2
θ
We also know from the definition of cotangent that
cot
θ
=
1
tan
θ
. Squaring both sides, we obtain
cot
2
θ
=
(
1
tan
θ
)
2
=
1
2
tan
2
θ
=
1
tan
2
θ
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