Question

tan^2 thetha ka formula​

Answer 1

I don't understand your question.

Answer 2

Answer:

$1 + { \tan }^{2} \alpha = { \sec }^{2} \alpha \\ \\ {tan}^{2} \alpha = {sec}^{2} \alpha - 1 \\ \\ \\ \\ here \: \alpha = theeta \\ \\ \\ hope \: it \: helps \: u \\ \\ \\ \\ follow \: me$