Question

tan^2 tita cos^2 tita= 1- cos^2 tita prove the trigonometric identity​

Answer 1

$LHS = tan^{2} \theta \cdot cos^{2} \theta$

$= (sec^{2} \theta - 1) cos^{2}\theta$

$\boxed { \pink {Since,\: tan^{2}A = sec^{2}A - 1 }}$

$= sec^{2}\theta\cdot cos^{2}\theta - cos^{2}\theta \\= 1 - cos^{2}\theta$

$\boxed { \orange { secA \cdot cosA = 1 }}$

$= RHS$

$Hence\: proved$

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Answer 2

Step-by-step explanation:

tan² tita .cos² tita = 1-cos² tita

LHS =sin²tita/cos²tita .cos²tita

= sin²tita

=1- cos²tita

RHS=1-cos²tita

LHS =RHS.

PLZZ Make it as BRAINALLIST answer