Tan 22° and tan 23° are roots of X2+ax+b=0 then
1) a+b+1=0
2) a-b+1=0
3) b-a+1=0
4) a+b=1
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Answer:
2) a-b+1=0
Step-by-step explanation:
Given :-
tan22 ∘ and tan23 ∘ are roots of x2+ax+b=0
∴tan22∘+tan23∘ = −a
tan22∘.tan23∘ = b
tan(22+23) = 1−tan22∘ tan23∘
tan22∘ + tan23∘ 1−tan22∘ tan23∘ = tan22∘ + tan23∘1−b=−a
⇒a−b+1=0
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