Question

tan ( -225°) cot ( - 405°) - tan ( -765° ) cot ( 675°) = 0 , Prove

Answer 1

Answer:

I hope this help you

Answer 2

anser:

tan(225)cot(405)+tan(765)cot(675)

tan405/(tan405) -(cot675/cot675)=0

explanation...

since

tan(180- theta)=-tan theta

tan(180+225)=-tan(405)

-cot(405)= -(1/tan(405))

-tan405/-tan405=1...................eq1

and ,

(90+theta)=-tan(theta)

cot(675+90)=-tan(765)

-(tan(-765)/(tan(-765)=-1........................eq2

add eq1 and eq2 we get

1-1=0

proved