tan^245-cos^230=xsin45cos45.then find x
lekhahasa:
where is x in the question
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Answered by
6
tan^2 45 - cos ^2 30 =x sin45cos45
1- cos^2 30 = x×1/root2 × 1/root 2
sin^2 30 = x × 1/2
(1/2)^2= x × 1/2
1/2 = x
x = 1/2
1- cos^2 30 = x×1/root2 × 1/root 2
sin^2 30 = x × 1/2
(1/2)^2= x × 1/2
1/2 = x
x = 1/2
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Answered by
5
tan²45-cos²30=x×sin 45×cos 45
1²-(√3/2)²=x×(1/√2)×(1/√2)
1-(3/4)=x×1/2
1/4=x×1/2
x=1/4×2
x=1/2
1²-(√3/2)²=x×(1/√2)×(1/√2)
1-(3/4)=x×1/2
1/4=x×1/2
x=1/4×2
x=1/2
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