Tan^2a÷1+tan^2a + cot^2a÷1+cot^2a =1
Answers
Answered by
2
(tan^2a/1+tan^2a)+(cot^2a/1+cot^2a)
=(tan^2a/sec^2a) +(cot^2a/cosec^2a)
=(sin^2a/cos^2a x cos^2a) +(cos^2a/sin^2a x sin^2a)
=sin^2a + cos^2a
=1
=(tan^2a/sec^2a) +(cot^2a/cosec^2a)
=(sin^2a/cos^2a x cos^2a) +(cos^2a/sin^2a x sin^2a)
=sin^2a + cos^2a
=1
Similar questions
Social Sciences,
7 months ago
Geography,
7 months ago