Question

tan (2A+A)= ?



answer it fast I will mark as brainlist for correct answer​

Answer 1

Answer:

tan3x

=tan(x+2x)

=tanx+tan2x1−tanxtan2x

=tanx+tan(x+x)1−tanxtan(x+x)

=tanx+tanx+tanx1−tanxtanx1−tanxtanx+tanx1−tanxtanx

=tanx+2tanx1−tan2x1−2tan2x1−tan2x

=tanx−tan3x+2tanx1−tan2x1−tan2x−2tan2x1−tan2x

=3tanx−tan3x1−3tan2x

Answer 2

Answer:

tan(3A)=

$\frac{3tana - {tan}^{3} a}{1 - 3 {tan}^{2} a}$