Math, asked by Anonymous, 1 year ago

tan 2A= cos( A- 18 )where 2A is an acute angle find the value of A

Hrishu1: The question is wrong Cos= Cot

Answers

Answered by Anonymous

Tan2A can be written as=
Cot(90-2A)
by equating
Cot(90-2A)= Cot(A-18)
90-2A=A-18
90+18=3A
108=3a
108÷3=A
36=A

Anonymous: m sleeping sorry

Anonymous: but say

Hrishu1: Can you prove the Converse of thales theorem or bpt by any other way.(Out of the books method).

Anonymous: Sry I have not done bpt converce

Anonymous: I think its not important

Anonymous: converse of Pythagoras is important

Hrishu1: oh sorry for disturbing by the way good night have sweet dreams.

Hrishu1: Im signing off

Hrishu1: byer

Anonymous: :)

Answered by harendrachoubay

Step-by-step explanation:

We have,

$\tan 2A=\cot (A-18)$

To find, the value of ∠A = ?

∴ $\tan 2A=\cot (A-18)$

⇒ $\tan 2A=\tan[90-(A-18)]$

[ ∵ $\tan(90-\theta)=\cot \theta$ ]

⇒ $2A=90-(A-18)$

⇒ $2A=90-A+18$

⇒ $2A+A=108$

⇒ $3A=108$

⇒ $A =\dfrac{108}{3}$ =36°

Hence, the value of ∠A = 36°.

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