Math, asked by Pratikjaiswal51031, 9 months ago

Tan^2A+cot^2A=sec^2A+cosec^2A

Answers

Answered by suggulachandravarshi
0

Answer:

tan2A + cot2A + 2 = cosec2A sec2A

Take the LHS:

tan2A + cot2A + 2

tan2A + cot2A + 1 + 1

tan2A + 1 + cot2A + 1

Since, tan2A + 1 = sec2A and cot2A + 1 = cosec2A

sec2A + cosec2A

1/cos2A + 1/Sin2A

(Sin2A + Cos2A) / cos2A Sin2A

1/ cos2A sin2A

Sec2A cosec2A= RHS

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