Math, asked by abhijeet1711, 1 year ago

tan^2A/sec^2A+cot^2A/cosec^2A=1

Answers

Answered by musicalindia9pcwaap

0

tan^2A/sec^2A+cot^2A/cosec^2A
=sin^2A/cos^2A×cos^2A+cos^2A/sin^2A×sin^2A
=sin^2A+cos^2A
=1
Becz (sin^2x+cos^2x=1)

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