tan^2A-sin^2A=sin^2Atan^2A
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Answered by
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hey !!!
from LHS
tan²A - sin² A
=> sin²A / cos²A - sin²A
=> sin²A -cos²A × sin²A /cos²A
=] sin²A (1 - cos²A )/cos²A
=> sin²A × sin²A /cos²A
=> sin⁴A /cos²A
=>sin²A×sin²A/cos²A
=> tan²A × sin²A
=> sin²A × tan²A RHS prooved
Rajukumar111
from LHS
tan²A - sin² A
=> sin²A / cos²A - sin²A
=> sin²A -cos²A × sin²A /cos²A
=] sin²A (1 - cos²A )/cos²A
=> sin²A × sin²A /cos²A
=> sin⁴A /cos²A
=>sin²A×sin²A/cos²A
=> tan²A × sin²A
=> sin²A × tan²A RHS prooved
Rajukumar111
Answered by
0
Heya!!!
Here is your answer,
Hope it helps you,
Thank you.
Here is your answer,
Hope it helps you,
Thank you.
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