Math, asked by masonani, 1 year ago

tan^2A-sin^2A=tan^2A.sin^2A
Prove the above identity

Answers

Answered by saniya545

2

Answer:

hope it helps.......#

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Answered by shaileshagrawal200

1

Answer :

LHS; tan∧2A-sin∧2A=(sin∧4A)/(cos∧2A)

RHS; tan∧2A.sin∧2A=(sin∧4A)/(cos∧2A)

LHS=RHS

Step-by-step explanation:

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