Math, asked by pokhrelganesh100, 13 days ago

tan^2B/cos^2A-tan^2A/cos^2B=tan^2B-tan^2A

Answers

Answered by YOGESHRANE

0

Step-by-step explanation:

tan2a−tan2b=cos2a.cos2bsin2a−sin2b

LHS tan2a−tan2b=cos2asin2a−cos2bsin2b =cos2a.cos2bsin2acos2b−sin2bcos2a

cos2b=1−sin2b

cos2b=1−sin2b

Therefore, cos2a.cos2bsin2a(1−sin2b)−sin2b(1−sin2a)

=cos2a.cos

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