tan^2theta(1-sin^2theta)=sin^2theta
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Heya mate,
tan^2theta(1-sin^2theta)=sin^2theta
Lhs
= tan^2theta(1-sin^2theta)
=tan^2 theta. Cos^2 theta [since, 1-sin^2theta=cos^2 theta]
=sin^2 theta/cos^2 theta. Cos^2 theta[since tan^2 theta= sin^2 theta/cos^2 theta ]
=sin^2 theta
=Rhs
PROVED
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Mark as brainliest if it does so
tan^2theta(1-sin^2theta)=sin^2theta
Lhs
= tan^2theta(1-sin^2theta)
=tan^2 theta. Cos^2 theta [since, 1-sin^2theta=cos^2 theta]
=sin^2 theta/cos^2 theta. Cos^2 theta[since tan^2 theta= sin^2 theta/cos^2 theta ]
=sin^2 theta
=Rhs
PROVED
HOPE it helps ya
Mark as brainliest if it does so
Answered by
0
hope this will help uh .....
nd plz mark as brainliest ....
nd plz mark as brainliest ....
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