tan^2thetacos^2theta = 1-cos^2theta
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♀ Question ♀
Prove that
♀ Solution ♀
LHS =
[/tex]
= \frac{ {sin}^{2 \: θ } }{ {cos}^{2 \: θ} } \times {cos}^{2} θ [/tex]
= RHS
Hence Proved!
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Step-by-step explanation:
L.H.S
Tan^2theta×cos^2theta
=sin^2theta/cos^2theta×cos^2theta (tan theta= sin theta/ cos theta)
=sin^2theta
R.H.S
1-Cos^2theta
=sin^2theta
L.H.S=R.H.S
Hence proved
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