Question

tan^2tita+cot^2tita-sec^2tita×cosec^2tita =?​

Answer 1

Answer:

-2 sec^2 x

Step-by-step explanation:

LET THETA BE X FOR CONVENIENCE

TAN^2 X=SIN^2 X/COS^2 X

COT^2 X=COS^2 X/SIN^2 X

TAN^2 X+COT^2 X=(SIN^ 4 X+COS ^4 X)/(SIN^2 X*COS^2 X)

SEC^2 X* COSEC^2 X=1/SIN^2X*COS^2X

sin^4 x+cos^4 x=1-2sin ^2 x

finally

ans---2sin^ 2 x/cos^ 2 x * sin^2 x

=-2 sec^ 2 x