Question

tan ^3 A upon sec ^2 A + cot ^3 A upon cosec ^2 A

Answer 1

Taking the L.H.S,

(1 – cos2 A) cosec2 A

= (sin2 A) cosec2 A [∵ sin2 A + cos2 A = 1 ⇒1 – sin2 A = cos2 A]

= 12

= 1 = R.H.S

– Hence Proved

Answer 2

Hope this helps you .....