tan= 3(where e is acute), then find the value of 1 +cos
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Answer:
tanθ=3–√⇒tan2θ=3⇒sec2θ=4⇒secθ=±2⇒cosθ=±12 .
Now, cosθ=−12⇒tanθ=−3–√,
so
cosθ=12⇒1+cosθ=32
This is your answer
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